Question

a Man Standing between two vertical walls 680m apart.he claps his hands and hears two distant echoes 0.9 seconds and 1.1 second respectively .what is the speed of sound in the air​

Answer 1

Answer:

$\huge\underline\bold\red{Given!!}$

$time \: of \: first \:echo \: t1 = 0.9s$

$time \: of \: second \: echo \: t2 = 1.1s$

$distance \: between \: man \: and \: wall,$

$\: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: d = 680m$

$\huge\underline\bold\red{To find!!}$

$speed \: of \: sound \: in \: air,c =?$

$\huge\underline\bold\red{Answer!!}$

$speed \: of \: sound \: in \: air ,c = 2 \frac{d}{t}$

$\: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: c = \frac{2d}{t1} + t2$

$\: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: c = \frac{2 \times 680}{(0.9 + 1.1)}$

$\: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: = \frac{2 \times 680}{2}$

$speed \: of \: sound \: in \: air,c = 680m/s$

hope it helps you ❤️ ✨

Answer 2

Answer:

hope it helps you...........❤️❤️