Question

A man standing in a lift carrying a bag of 5kg.if lift moves vertically downwards

Answer 1

Answer:

The tension force in handle of bag is 73.5 N.

Explanation:

Given that,

Mass of bag = 5 kg

Suppose, If lift moves vertically downwards with acceleration g/2. Find the tension force in handle of bag.

There are three forces acting on the bag,

Weight = mg

Upward tension = T

Upward force = ma

Here, acceleration $a = \dfrac{g}{2}$

We need to calculate the tension

Using equation of motion

$ma=T-mg$

$T=m(a+g)$

Where, m = mass of bag

T = tension

g = acceleration due to gravity

Put the value into the formula

$T=5\times(\dfrac{g}{2}+g)$

$T=5\times(\dfrac{9.8}{2}+9.8)$

$T=73.5\ N$

Hence, The tension force in handle of bag is 73.5 N.