Question

A man standing in a lift holds a spring balance with a load of 5kg suspended from it . What would be the reading of the balance when the lift is moving down with an acceleration of 3.8m/s2 ?

Answer 1

Given: A man standing in a lift holds a spring balance with a load of 5 kg suspended from it .

To find: What would be the reading of the balance when the lift is moving down with an acceleration of 3.8 m/s^2 ?

Solution:

• Now we have given that the load is 5 kg.

                 So R = mg

• We know that when lift goes downward then the apparent weight decreases. so:

                 R = m x (g - a)

• So putting the values, we get:

                 R = 5 x ( 9.8 - 3.8 )  

                 R = 5(6)

                 R = 30 N

Answer:

              So the reading of the balance when the lift is moving down with an acceleration of 3.8 m/s^2 is 30 N.

Answer 2

Answer:

R=mg

R=m×(g-a)

R=5×(9.8-3.8)

R=5(6)

R=30N

Here's your answer...