Question

A man standing in an open truck moving at a speed of 30m/s throwing a stone at 10m/s in the same direction as the truck at an angle of 45degrees
A)how far does the stone travel in the horizontal direction

Answer 1

Answer:

10m

Explanation:

V1=30m/s, V2=10m/s

In same direction,

THEREFORE, v1-v2=20m/s

To find the distance/height=v^2sin^2theta/2g

Theta=45°

H= 20^2*sin^2(45)/2*10

=400×(1/root(2))^2/20

=400×1/2/20

=200/20

H=10m

The stone travel 10m in horizontal direction..