Physics, asked by nusrath6242, 9 months ago

A man standing in front of a vertical cliff fires a gun. He hears the echo after 3 s. On moving closer to the cliff by 82.5 m, he fires again and hears the echo in 2.5 s. What is the speed of sound? *
4 points
340m/s
350m/s
330m/s

Answers

Answered by sucharithaa
0

Answer:

Explanation:

First case

Distance=x

Time=3s

X/1.5=Speed of sound

Second case

If he moves 82.5m close then

Distance=x-82.5m/1.25

We know that

x/1.5s=x-82.5m/1.25s

x*0.25s=(x- 82.5)*0.3s

0.25x=0.3x-24.75

24.75m=0.05x

2475/5=x

495m=x

Speed of sound=495m/1.5=330m/s

Hope it helps

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