A man standing in front of a wind turbine with blades 30m long. The angle of elevation from an eye of man to the top of blade is 34° and the top of the tower is 25°. Calculate the distance between the bottom of turbine and the position of man.❤️
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* Solution *
Let h= height of second tower, d=distance between two towers
height of first tower = 30 m
From given data,
d30=tan60∘=3
dh=tan30∘=31
3h=d,30=d3
h=10 m, d=103 m
Therefore, height of the other tower is 10m.
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Answer:
tan60
∘
=
BC
AB
=
3
⇒BC=
3
AB
Now ΔB=DC+BC=50+
3
AB
tan30
∘
=
3
1
=
ΔC
AB
=
50+
3
AB
AB
⇒50+
3
AB
=
3
AB
⇒50
3
+AB=3AB
Ab=25
3
= Height of tower
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