Question

A man standing on a boat 8 m above water level he observes the angle of elvation on the top of the hill as 60 and angle of depression of the base of the hill as 30 calculate the distance of the hill and height of the hill

Answer 1

height of the hill is 33mand distance is √3*8m

Answer 2

____Heyy Buddy ❤____

____Here's your Answer..______

Given,

BC = x cm.

CD = 8cm..

DE = Ycm.



In Triangle ABC ,

Tan 60° = x/y

$\sqrt{3} = x \div y$
$y = x \div \sqrt{3}$
----------(1)

In Triangle ADC,

Tan 30° = 8 ÷ y

$1 \div \sqrt{3} = 8 \div y$
$= > \: y = 8 \sqrt{3}$

Equating eq 1 and 2, we get..

$8 \sqrt{3 } = x \div \sqrt{3}$
$= > \: x = 8 \times \sqrt{3} \times \sqrt{3}$
$= > \:x = 24$
So,

Height of Hill = 24 + 8

=> 32 cm.

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