A man standing on a platform observes a train going in one direction takes 4 seconds to pass him. Another train of the same length going in the opposite direction takes 5 seconds to pass him. What would be the time taken by the two trains to cross each other?
Answers
Answered by
25
Solution 40 seconds
because
s= d/t
let s1 be the speed of 1st train = d/4
let s2 be the speed of 2nd train = d/5
relative speed in same direction s= s1 - s2
= ( d/4 - d/5 )
= d/20
now t = d/s ( time taken to cross each other moving in same direction so d= 2d because 2 trains of same length d )
t =
=
=40 sec
Thus the time taken to cross would be 40 seconds
because
s= d/t
let s1 be the speed of 1st train = d/4
let s2 be the speed of 2nd train = d/5
relative speed in same direction s= s1 - s2
= ( d/4 - d/5 )
= d/20
now t = d/s ( time taken to cross each other moving in same direction so d= 2d because 2 trains of same length d )
t =
=
=40 sec
Thus the time taken to cross would be 40 seconds
sachusoman:
Hi,,relative speed = (d/4 + d/5) = (9d/20). So answer will be 40/9 sec. because trains are in the opposite direction. But your method helped me a lot. Thank you
Answered by
8
the time taken for the trains to cross each other is opposite direction must be 40/9 seconds
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