Question

A man standing on a sidewalk looks up at the roof edge of a building. The building is 40 feet tall and the man stands 12 feet from the building.What is the measure of the man's angle of inclination from where he stands?Enter your answer, rounded to the nearest degree, in the box.

Answer 1

the angle is 73.3 degree

Answer 2

The man's angle of inclination from where he stands is 73.30°.

Step-by-step explanation:

Given:

Height of building AB = 40 feet

Man standing away from building BC = 12 feet

We need to find he measure of the man's angle of inclination from where he stands i.e m ∠C

Now We Know that;

$tan \angle C = \frac{Opposite \ side}{Adjacent \ side}= \frac{AB}{BC}  = \frac{40}{12}  = 3.33$

Now taking Inverse of tan on both side we get;

$tan^{-1}(tan \angle C) = tan^{-1} (3.33) = 73.30$

m∠ C = 73.30°

Hence the man's angle of inclination from where he stands is 73.30°.