Question

a man standing on a window of the first floor of a building observe that the angle of depression of a dustbin which is 10 m from the foot of the building is 45 degree. he climbs to the window of the second floor directly above the first floor and observe the angle of depression of the dustbin to be 60 degrees .calculate the height of the first floor and the second floor.

Answer 1

hay here is ur ans. .....

Answer 2

Answer: The answer to this question is 10m for the 1st floor.

               7.32m for the 2nd floor.

Step-by-step explanation on:

Always try to make a rough diagram and solve such problems, it makes it easy to understand.

Let the point where the man is standing on window be A.

Let the point where the dustbin is there be B.

Let the foot of the building be C.

So according to the given details,

CB = 10m.

angle (ABC)= 45 degrees.

Let the point of the 2nd floor be P.

We must understand what the angle of depression is: It is the angle measured below the horizontal level.

In triangles ABC and PBC, we use trigonometric ratios as follows:

$tan(45) = \frac{AC}{BC} \\\\AC = BC =10m.\\tan(60)=\frac{CP}{BC} \\\\CP= BC\sqrt[2]{3} \\CP = 10\sqrt[n]{3} \\CP = 17.32m\\\\2nd floor height =CP -AC \\ = 7.32m$

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