a man standing on the deck of a ship which is 10m above the water level , observes the angle of elevation of the top of a hill is 60 degreeand the angle of depression of the base angle of the hill is 30 degree . calculate the distance of the hill?
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In ΔBDC
tan 30= 10/x
1/√3 = 10/x
x= 10√3
x= 17.32m
In ΔAEC
tan60= AE/CF
√3= AE/ 10√3
AE= 30
height of hill = 30+10= 40m
distance of the hill = 17.32m
tan 30= 10/x
1/√3 = 10/x
x= 10√3
x= 17.32m
In ΔAEC
tan60= AE/CF
√3= AE/ 10√3
AE= 30
height of hill = 30+10= 40m
distance of the hill = 17.32m
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