Question

a man standing on the top of ship 10 metre above the sea sees the top of an angle of elevation 80 degree and its foot at an angle of depression 30° how far ? What is the height​

Answer 1

Answer:

Let AB=10m, cliff of a ship where man is standing

Let CE be the hill.

CD=AB=10m

In △ADE

tan60°=

x

h

3

x=h

x=

3

h

⟶(1)

In △ABC

tan30°=

x

10

3

1

=

x

10

x=10

3

⟶(2)

We have two equations (1) & (2), Multiplying them we get,

x

2

=10h

h=30m

∴CE=CD+DE=10+30=40m