Question

A man standing stationary with respect to horizontal conveyor belt that is accelerated with one metre per second square find the net force on a man is coefficient of static friction is 0.2 up to what acceleration of the belt can the man continue to be stationary related to the belt if mass of a man is 55 kg

Answer 1

Answer:

Mass of the man, m = 65 kg

Acceleration of the belt, a = 1 m/s2

Coefficient of static friction, μ = 0.2

The net force F, acting on the man is given by Newton’s second law of motion as:

= 65 × 1 = 65 N

The man will continue to be stationary with respect to the conveyor belt until the net force on the man is less than or equal to the frictional force fs, exerted by the belt, i.e.,





∴a' = 0.2 × 10 = 2 m/s2

Therefore, the maximum acceleration of the belt up to which the man can stand stationary is 2 m/s2.

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Explanation: