Question

A man stands before a large wall at a distance of 100 m and claps his hands at regular intervals. In such way that echo of a clap merges with the next clap. If he has to clap 5 times during every 3 seconds, find the velocity of sound in air.​

Answer 1

Answer:

The sound travels to the wall and back, or 100+100 m = 200 m in this time (= 0.6 sec). Hence velocity (distance per unit of time) is (200 m)/(0.6 sec) = 333.33 m/sec.

Explanation:

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Answer 2

Here is your answer dear..