Question

A man stands before a large wall at a distance of 50.0 m and claps his hands at regular intervals. Initially, the interval is large. He gradually reduces the interval and fixes it at a value when the echo of a clap merges with the next clap. If he has to clap 10 times during every 3 seconds, find the velocity of sound in air.

Answer 1

Answer ⇒ 333 m/s.

Explanation ⇒

When the echo comes back traveling a distance 2 × 50 m = 100 m, just then the next clap is executed.

The time between the consecutive claps   = 3/10 s

= 0.30 s.

Now, let the velocity of the sound be V, then

V = 100/0.3 m/s

V = 333 m/s

Hence, the speed of the sound is 333 m/s.

Hope it helps.

Answer 2

A man stands before a large wall at a distance of 50.0 m and claps his hands at regular intervals. Initially, the interval is large. He gradually reduces the interval and fixes it at a value when the echo of a clap merges with the next clap.❤️