Question

A man stands before a large wall at a distance of 50.0 m and claps his hands at regular intervals. Initially, the interval is large. He gradually reduces the interval and fixes it at a value when the echo of a clap merges every 3 seconds, find the velocity of sound in air. ​

Answer 1

Each clap must occur at the instant the echo of the last one returns.

Claps occur every

5

(3 seconds)

= 0.6 second.

The sound travels to the wall and back,

or 100+100=200 m in this time 0.6 sec

Hence velocity =

t

D

v =

(0.6sec)

(200m)

= 333.33m/sec.

Answer 2

Answer:

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