Physics, asked by sai0112, 1 year ago

a man stands between two cliffs and fires a gun. he hears two successive echos after 3 sec and 5 sec . the distance between the two clifs is(speed of sound = 340m/s )

Answers

Answered by nishant124
0
First case
d = t * s = 6*340 = 2040 m
Second Case
d = t * s = 10*340 = 3400 m
Total Distance = 2040 + 3400 = 5440 m

sai0112: A man stands between two cliffs and fires a gun. he hears two successive echos after 3 sec and 5 sec . the distance between the two clifs is(speed of sound = 340m/s )
sai0112: this one
nishant124: How
sai0112: options are 1340m,1330m,1360m or 1310m
nishant124: Is the answer 2720
sai0112: no
nishant124: I didn't see the options
gschandrakutty: Yeh iam correct...
gschandrakutty: Get did you got my Answer...
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Answered by gschandrakutty
0

Case1,

d'=t×speed

d'=3/2×340

d'=510

Case2

d''=5/2×340

d''=850


Distance=d'+d''

=850+510=1360m

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