a man stands between two cliffs and fires a gun. he hears two successive echos after 3 sec and 5 sec . the distance between the two clifs is(speed of sound = 340m/s )
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First case
d = t * s = 6*340 = 2040 m
Second Case
d = t * s = 10*340 = 3400 m
Total Distance = 2040 + 3400 = 5440 m
d = t * s = 6*340 = 2040 m
Second Case
d = t * s = 10*340 = 3400 m
Total Distance = 2040 + 3400 = 5440 m
sai0112:
A man stands between two cliffs and fires a gun. he hears two successive echos after 3 sec and 5 sec . the distance between the two clifs is(speed of sound = 340m/s )
Answered by
0
Case1,
d'=t×speed
d'=3/2×340
d'=510
Case2
d''=5/2×340
d''=850
Distance=d'+d''
=850+510=1360m
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