A man stands on a tall ladder of height h. He leans over
a little too far and falls off the ladder. If his mass is m,
what is his potential energy right before he falls? Explain.
Answers
Answered by
9
Explanation:
Height = h
Mass of man = m
Potential energy of man before falling will be
= mass × height × gravity
= mgh.
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Answered by
3
Answer:
Right before he falls his potential energy is 0.
Explanation:
Potential energy = mgh
Right before he falls his height (h) from the ground is O.
=> m x g x (0)
=> 0J
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