Question

A man start his motion from rest with uniform acceleration of 1m/s², then his average velocity equals 1m/s during ____ from starting his motion
(What is the duration to get to an average velocity of 1m/s)

Answer 1

Explanation:

u = 0

v= 1 m/s

a = 1m/s^2

t = ?

now find distance

v^2 - u^2 = 2as

1^2 - 0^2 = 2(1)s

1=2s

s= 1/2

now find time

s= ut+1/2at^2

s= 1/2(1)t^2

1/2 = 1/2(1)t^2

1/2 = 1/2(t^2)

t^2 = 1/2(2/1) = 1

time taken to gain 1 m/s velocity it need 1 second