Question

A man start pushing a merry-go-round with a torque of 10 N-m. It has a moment of inertia of 100 kg m ^ 2 . What is its rotational speed after 3 seconds, assuming it start at rest.​

Answer 1

Explanation:

torque = 10 Nm

I = 100Kg m²

In rotational mechanics,

torque = momen of inertia x angular acceleration

10 = 100 x angular acceleration

10 = 100 x a

a = 10 rad /s²

W = Wo + a t

W = 0 + 10 x 3

W = 30 rad /s