Question

a man start walking and cover 3 meters in north direction then he turn right and cover 4 metre. from this point again he walks north direction and covered 3 meters distance then he take another right and cover 4 metre distance

find the total distance travel and total displacement​

Answer 1

Answer:

14 m (distance)

10 m (displacement)

Explanation:

Let north, east be represented by N, E.

According to question:

⇒ 3m in North = 3N,  then

⇒ 4m in East(right) = 4E , then

⇒ 3m in North = 3N , then

⇒ 4m in East(right) = 4E

Total displacement = 3N + 4E + 3N + 4E

 ⇒ 6N + 8E

As North and east are at right angle to each other, we can't add them directly.

Using Pythagoras theorem,

Displacement = √6² + 8² = 10

Displacement is 10 m

But in terms of distance, we can add it directly as it doesn't depend on direction, distance = 6 + 8 = 14 m

Answer 2

Answer:

Given :-

a man start walking and cover 3 meters in north direction then he turn right and cover 4 metre. from this point again he walks north direction and covered 3 meters distance then he take another right and cover 4 metre distance

To Find :-

The total distance travel and total displacement

Solution :-

Finding the total distance

Distance = 3 + 3 + 4 + 4

Distance = 6 + 8

Distance = 14 m

Finding total displacement

We may observe that the North and East make a right angle triangle.

By using Pythagorean theorem

H² = P² + B²

$\sf \: {H}^{2} = {6}^{2} + {8}^{2}$

$\sf \: {H}^{2} = 36 + 64$

$\sf \: {H}^{2} = 100$

$\sf \: {H} = \sqrt{100}$

$\sf \: H = 10 \: m$