Question

a man start walking and cover 3 meters in north direction then he turn right and cover 4 metre. from this point again he walks north direction and covered 3 meters distance then he take another right and cover 4 metre distance

find the total distance travel and total displacement​

Answer 1

Answer:

14 m (distance)

10 m (displacement)

Explanation:

Let north, east be represented by N, E.

According to question:

⇒ 3m in North = 3N,  then

⇒ 4m in East(right) = 4E , then

⇒ 3m in North = 3N , then

⇒ 4m in East(right) = 4E

Total displacement = 3N + 4E + 3N + 4E

 ⇒ 6N + 8E

As North and east are at right angle to each other, we can't add them directly.

Using Pythagoras theorem,

Displacement = √6² + 8² = 10

Displacement is 10 m

But in terms of distance, we can add it directly as it doesn't depend on direction, distance = 6 + 8 = 14 m

Answer 2

$\huge\fbox\pink{✯Answer✯}$

$\huge\boxed{\fcolorbox{purple}{ink}{GIVEN:}}$

• 14 m (distance)

• 10 m (displacement)

$\huge\boxed{\fcolorbox{red}{ink}{SOLUTION:}}$

• Let north, east be represented by N, E.

$According \: to \: question:$

⇒ 3m in North = 3N,  then

⇒ 4m in East(right) = 4E , then

⇒ 3m in North = 3N , then

⇒ 4m in East(right) = 4E

$Total \: displacement \\ = 3N + 4E + 3N + 4E$

 

$⇒ 6N + 8E$

We know that,

• As North and east are at right angle to each other, we can't add them directly.

Using Pythagoras

theorem,

$Displacement \\ = √6² + 8² = 10$

$Displacement \: is \: 10 m$

• But in terms of distance,

we can add it directly as it doesn't depend on direction, distance

$= 6 + 8 = 14 m.$

$\huge\boxed{\dag\sf\red{Thanks}\dag}$