Math, asked by nusaibamyreen, 6 months ago

A man started at 8:00 AM from his home, walked at the rate of 3 km/hr and reached his office 45 mins late. The next day he started at the same time and walked at the rate of 5km/hr and reached his office 15 mins earlier. What is the distance between his office and home?

Answers

Answered by ninjatall12
3

Answer:

3.75Km

Step-by-step explanation:

Distance = Speed x Time

3x(T+45) = D

6x(T-15) = D

3T+135=6T-90

3t=225 Min

t=75 Min

75 Min = 1.25 H

3KM/hrx1.25Hours=3.75Km

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