Question

A man started his job with a certain monthly salary and earned a fixed increment every year.

His salary was 15,000 after 5 years service and 19,000 after 10 years service. What was his

starting salary and his annual increment?​

Answer 1

Step-by-step explanation:

Given A man started his job with a certain monthly salary and earned a fixed increment every year. His salary was 15000 after 5 years' service and 19000 after 10 years' service. What was his starting salary and his annual increment.

Let the initial salary be p and increment be n

So m + 5n = 15,000

So m + 10n = 19,000

Now solving we get, on subtracting the equations

So – 5n = - 4,000

Or n = 4,000 / 5

Or n = 800

Now m + 5n = 15,000

Or m + 5(800) = 15,000

Or m = 15,000 – 4000

Or m = 11,000

Therefore his starting salary was Rs 11,000 and increment every year was Rs 800

Answer 2

$<font color="purple">$★FIND:

His starting salary=?

and

His annual increment=?

$<font color="red">$★GIVEN,

Salary:

➡️Rs.15000 after 5 years

➡️Rs.19000 after 10 years

$<font color="green">$★SOLUTION:

Let, his starting salary be Rs.'X' says

and his fixed annual increment be Rs.'Y' says

➡️Salary after 5 years = X+ 5Y

➡️According to question

➡️X+5Y= 15000.. EQ1

➡️And salary after 10 years =X+10Y

➡X+️10Y= 19000.. EQ2

$<font color="orange">$➡️SUBTRACTING EQ1 & EQ2

➡️X+5Y-X-10Y=15000-19000

➡️-5Y=-4000

➡️Y=4000/5

➡️Y=800

sub, Y=800 in EQ1 or EQ2

$<font color="black">$EQ1➡️

$<font color="green">$➡️X+5Y=15000

➡️X+5(800)=15000

➡️X+4000=15000

➡️X=15000-4000

➡️X=11000

$<font color="black">$EQ2➡️

$<font color="purple">$➡️X+10Y=19000

➡️X+10(800)=19000

➡X+8000=19000

️➡️X=19000-8000

➡️X=11000

$<font color="red">$So, wherever u substitute in EQ1 or EQ2 you will get the same value..

➡️Starting salary (X)= Rs.11000

➡️And Annual increment (Y)= Rs.800

$<font color="violet">$★VERIFICATION :

(X,Y)=(11000,800)

$<font color="black">$EQ1➡️

$<font color="violet">$➡️X+5Y=15000

➡️11000+5(800)=15000

➡️11000+4000=15000

➡️15000=15000

$<font color="black">$EQ2➡️

$<font color="violet">$➡️X+10Y=19000

➡11000+10(800)=19000

️➡️11000+8000=19000

➡️19000=19000

SO, HENCE PROVED BY VERIFICATION.