A man started his journey 40 minutes later than usual time due to family fight. But due to urgent work he increased his speed to 160% of his usual speed so he reached 35 minutes earlier at his destination. What is the usual time taken by him for the journey? घरेलू झगड़े की वजह से एक व्यक्ति एक यात्रा पर अपने निर्धारित समय से 40 मिनट देरी से निकलता है लेकिन आवश्यक कार्य हेतु वह अपनी चाल सामान्य चाल का 160% कर देता है और ऑफिस 35 मिनट पहले ही पहुँच जाता है। ऑफिस पहुँचने के लिए लिया जाने वाला नियत समय क्या था?
Answers
Given :- A man started his journey 40 minutes later than usual time due to family fight. But due to urgent work he increased his speed to 160% of his usual speed so he reached 35 minutes earlier at his destination. What is the usual time taken by him for the journey ?
Answer :-
Let us assume that, usual speed of man is 10km/h and total distance coverd for work is D km .
so,
→ Usual time taken to go for work = D/S = (D/10) hours .
now,
→ New speed = 160% of 10 = (160 * 10)/100 = 16km/h .
then,
→ Time taken to reach at work = (D/16) hours .
A/q,
→ (D/10) - (D/16) = (40 + 35) minutes
→ (8D - 5D)/80 = (75/60)
→ 3D/80 = 5/4
→ 3D = 100
→ D = (100/3) km .
therefore,
→ Usual time taken to go for work = (100/3) * (1/10) = (10/3) hours (Ans.)
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