a man started on a bicycle on a journey of 26 km but after he had a part of the way at a speed of 20 km per hour, his bicycle broken down. he spent 15 minutes trying to repair it and then completed his journey by walking at a speed of 5 km per hour. if the whole journey took two hours, then how far did he walk?
Answers
Answer:
He walked 1.45 km far.
Step-by-step explanation:
Given data
Distance = 26 km,
Speed = 20 km / hr.
Spending time 15 mts
Walking speed = 5 km/hr’
Complete journey?
Step 1:
Total time is 2 hrs
he rested for 15 min =15/60 = 1 / 4 hr
Step 2:
Time taken in travelling= 2 -1 / 4 = 7 / 4 hr
T is the time taken during cycling
7 /4 -T is the time taken during walking
Step 3:
So 7/4 = T / 5 + T / 1
7 / 4 = 6T / 5
35 = 24T
T= 1.45
Answer:
Step-by-step explanation:
Given total distance = 26km
Speed of train 20km/ hr
Let the distance traveled by him in train be d km
t1 be time travelled by him in train
t1= d/20
He wasted 15 minutes in repair converting it into hours
t2=15/60 = 1/4
Let t3 be time travelled by in on walk
Speed= 5km/ hr
D = 26-d
t3=(26-d)/5
Total time is 2 hours
t1+t2+t3=2
d/20+1/4+(26-d)/5=2
(d+104 -4d)=(7/4)×20
-3d=-69
d=23
Here d is distance traveled by him in train
We need walking distance
i.e, 26-d = 26-23=3.
Therefore 3 km is answer