A man started walking frorn his house towards south. after walking 6 km, he turned to his left walked 5 km after. then he walked further 3 km after turning left. he then turned to his left and continued his walk for 9 km. how far is he away from his house?
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He is 5 km from his house.......
Pythagorus in triangle ABC
Pythagorus in triangle ABC
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He is 5km away from his house.
* The figure should be as given below. An imaginary triangle AOB has been formed.
* The length of side AB is determined using Pythagoras theorem.
AB^2 = AO^2 + BO^2
AB^2 = 16+9
So AB = 5
Therefore, the distance between his house and final destination is 5km.
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