A man starting from rest accelerated his automobile and achieved a velocity of 60 m/s in
10 seconds. After that he applies brake and the velocity decreases to 10 m/s in 1 second
Calculate the acceleration in both the cases.
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Answer:
sorry dont knowww really...
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case 1:-
v= u+at
60=0+10a
acceleration= 6m/s^2
case 2:-
v=u+at
10= 6+a
acceleration= 4m/s^2
( in case of decreasing acceleration, we call it as deceleration)
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