Question

A man starts driving in an open gypsy at t = 0 in rainy weather.
Assume that speed of gypsy varies with time as v = kt. At t = 1 s, he observes rain is falling vertically to him. At t = 2 s, he finds rain drops hitting him at an angle of 45° with vertical. Assuming velocity of rain to be constant, the angle with vertical at which rain
is actually falling is tan-'(x). The value of x is ??​

Answer 1

Answer:

which class of question is this

Answer 2

Given:

Value of t = 0 , 1 , 2 accordingly

Angle  = 45°

To Find:

The value of x

Explanation:

let V actual rain a Case-I,

at this gypsy  t = o

V observed by car on t as since rain.  ,

w => Vx-k=0

K a component of rain velocity is zero  .

Vx=K - t

case-2 =Rk 2v gypsy t=2s,

x=k 5.

V rain (gypsy but at sin= 45 ° - RP-ry] KI

cos tan 45:=k

1x=1

x = 1

Answer = 1