A man starts from a point and travels along a rectangular field of dimensions 500m×300m. When he reaches the diagonally opposite end ,find his distance and displacement.
Answers
Answer:
Here is your answer
Step-by-step explanation:
Distance:- Diagonally opposite means from one angle to another of a rectangle. Therefore, Distance = 500+300=800m
displacement will be done using Pythagoras theorem
A=B+C
A^2=B^2+C^2
A^2=(500)^2+(300)^2
A^2=250000+9000
A^2=259000
Therefore, A=Square root of 259000
A=508.9 m
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I Hope u got it :)
Answer:
Distance is the actual distance travelled by a person . When the man reaches diagonally opposite end , he must have covered both length and breadth once i.e. if he started from B to reach diagonally opposite D , he covered BC and CD .
So distance travelled = BC + CD
= 500 + 300
= 800 m
Displacement is the difference between the initial and final point . Since , his final point is D and initial point is B , the displacement thus becomes BD .
From Pythagoras theorem ,
\sf{hypotenuse}^{2} = {base}^{2} + {perpendicular}^{2}hypotenuse
2
=base
2
+perpendicular
2
BD² = BC² + CD²
\implies \tt BD = \sqrt{BC^2 + CD^2 }⟹BD=
BC
2
+CD
2
\begin{gathered} \tt = \sqrt{ {500}^{2} + {300}^{2} } \\ \\ \tt = \sqrt{250000 + 90000} \\ \\ \tt = \sqrt{340000} \\ \\ \tt \: = 100 \times 5 . 83 \: m \\ \\ \tt = 583 \: m(approx)\end{gathered}
=
500
2
+300
2
=
250000+90000
=
340000
=100×5.83m
=583m(approx)
\underline{\therefore \sf The\ distance\ is\ 800\ m\ and\ displacement\ is}\underline{\sf 583\ m}
∴The distance is 800 m and displacement is
583 m