a man starts from a pont and travels along a rectangular field of dimensions 500 × 300 when he reaches the diagonally opposite end find his distance and displacement
Answers
Answer:displacement ={(500)^2 + (300)^2]^1/2 i.e (340000)^1/2 =583m ( approx)
Distance=800m
Explanation:
Answer: 583 units
Explanation:
Considering the man walks on the borders of the rectangular field of dimensions, let us name the rectangle PQRS.
Suppose he starts at P, goes to Q covering 300 and the to R covering another 500. 300 + 500 would give us the distance travelled, not the displacement. Displacement is the shortest distance between the start point and the end point, meaning draw a straight line from initial point to final point
Since, he is present at diagonally opposite end, the diagonal's length would be the displacement. Also, if note that the triangle formed by the two sides and diagonal is a right angled triangle. By pythagoras theorem, diagonal is approx 583 units