A man starts from his home ‘A’ travels 2 km towards east to reach position ‘B’ in 1 hour, then takes right turn and travels 2 km in 0.5 hrs to reach position ‘C’. He takes right turn and travels 1 km in 0.5 hrs to reach position ‘D’. Find out (i) Distance travelled by man during his journey. (ii) His Displacement on reaching position D.
Answers
Answered by
2
Explanation:
The movement of the person are as shown in fig.
Clearly AB = 3 km
BC=3AB=(3×3)KM=9KM
CD=5AB=(5×3)KM=15KM
Draw AE ⊥ CD.
Then CE = AB = 3 km and
AE = BC = 9Km
DE = (CD-CE)=(15-3)Km = 12 Km.
In Δ AED, AD
2
=AE
2
+DE
2
= AD=(
9
2
+(12)
2
)km=15km
∴ Required distance = AD = 15 Km
Similar questions