Question

A man starts from his home ‘A’ travels 2 km towards east to reach position ‘B’ in 1 hour, then takes right turn and travels 2 km in 0.5 hrs to reach position ‘C’. He takes right turn and travels 1 km in 0.5 hrs to reach position ‘D’. Find out (i) Distance travelled by man during his journey. (ii) His Displacement on reaching position D.

Answer 1

Explanation:

The movement of the person are as shown in fig.

Clearly AB = 3 km

BC=3AB=(3×3)KM=9KM

CD=5AB=(5×3)KM=15KM

Draw AE ⊥ CD.

Then CE = AB = 3 km and

AE = BC = 9Km

DE = (CD-CE)=(15-3)Km = 12 Km.

In Δ AED, AD

2

=AE

2

+DE

2

= AD=(

9

2

+(12)

2

)km=15km

∴ Required distance = AD = 15 Km