Physics, asked by anjalimathur1101, 2 months ago

A man
starts from his
home & travels 6 km towards
east. He then turns left & traved 8 km along a
straight line. Find his distance travelled & displace-
ment​

Answers

Answered by Shreya762133
2

Explanation:

Distance traveled = OA+BA

= ( 6+8 ) km

= 14 km

\begin{gathered} b {o}^ {2} = \sqrt{b {a }^{2} + o {a }^{2} } \\ \sqrt{ {8}^ {2} + {6 }^{2} } \\ \sqrt{64 + 36 } \\ \ \sqrt{100} \\ = 10km\end{gathered}bo2=ba2+oa282+6264+36 100=10km

Displacement = 10 km

Explanation:

HOPE IT HELPS YOU

PLEASE MARK ME AS BRAINLIST

Attachments:
Answered by kesujaimithra
1

Answer:

hcfyjfejksyey it. vhzwgwnsk vg s

Similar questions