Question

A man starts from his home and travels 6km towards east .he then turn left and travels 8km along a straight line .find his distance travels and displacement

Answer 1

Answer: distance is 14 kilometre and displacement is 10 kilometre

Explanation: distance is the total length of the path and displacement is a distance between initial and final position the person travel in East 6 kilometre then he turns left means in north direction he travel 8 kilometre sodistance between initial and final position is the by Pythagoras theorem √6^2+8^2=displacement=10

Answer 2

Distance traveled = OA+BA

= ( 6+8 ) km

= 14 km

$b {o}^ {2} = \sqrt{b {a }^{2} + o {a }^{2} } \\ \sqrt{ {8}^ {2} + {6 }^{2} } \\ \sqrt{64 + 36 } \\ \ \sqrt{100} \\ = 10km$

Displacement = 10 km

Explanation:

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