a man starts from his home at 8 a.m. to his office he walks with a speed of 2 metre second inverse -1 on a road up to his office 3 kilometre away from his home he stays in the office upto 4 p.m. and returns to his home by bus which moves with a speed of 10 metre second inverse -1 calculate the time taken by a man to reach his office and time taken by the man to reach his home also plot (x minus t )graph of hismotion
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While going; v=2m/s , s=3km=3000m
Therefore, t=s/v
=3000m/(2m/s)= 1500s
While returning; v=10m/s , s=3km=3000m
Therefore, t=s/v
=3000m/(10m/s) = 300s
Sorry, their is a problem in attaching the v-t graph
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