Question

A man starts from rest accelerates at 1 metre per second squared in 2 seconds. The distance covered by the man will be:

Answer 1

Answer:

From the second equation of Kinematics for uniformly accelerating objects

The formula is

s = ut + at^2/2

Where,

s = displacement

u - initial velocity

a - acceleration

t - time

Here, initial velocity is zero because it starts at rest.

So,

Displacement here = 0(2)+1/2*(1)(2)^2 = 2 metres.

Hope this helps you !

Answer 2

Answer:2m

Explanation:u=0m/s

A=1m/s^2

T=2s

V=u+at

=2m/s

S=u+v/2×t

=2m