A man starts his job with a certain monthly salary and earns a fixed increment every
year. If his salary was Rs. 1500 after 4 years of service and Rs. 1800 after 10 years of
his service, what was his starting salary and what is the annual increment?
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man starts his job with a certain monthly salary and earns a fixed increment every year. If his salary was Rs 1500 after 4 year of service and Rs 1800 ...
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Let the starting salary of the man be Rs. x and the fixed annual increment be Rs. y. Then,
Salary after 4 years of service =Rs. (x+4y)
Salary after 10 years of service =Rs. (x+10y)
∴x+4y=1500 (i)
x+10y=1800 (ii)
Substracting equation (i) from equation (ii), we get
6y=300⇒y=50
Putting y=50 in equation (i), we get x=1300.
Hence the starting salary was Rs. 1300 and annual increment is Rs. 50.
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