a man starts to walk towards north with a uniform speed of 3 meters per second after 2 seconds he turned towards east and moves with a uniform speed of 4m/s for another 2 seconds. Calculate the displacement of the object after 4 seconds of the journey
Answers
Answered by
0
Distance covered in 25=v.t=10m v=5m/s
85=v.t=40m
His path :
Taking A are origin
A≡(0,.0)
D=(−30,−40)
(t=
v
d
=
5
40
=8s)
(1)Displacement =d(AD)=
40
2
+30
2
=
1600+900
=
2500
=
50m
(ii) Total distance =10+40+40=
90m
(iii) Avg. speed =
TotalTime
TotalDistance
=
2+8+8
90m
=
18
90
=
5m/s
(iv)Avg. velocity =
Totaltime
TotalDisplacement
=
18
50
=
2.78m/s
in
AD
direction
Similar questions