Question

A man starts walking with constant acceleration of 2 m/s2 in rain falling vertically downwards with constant speed of 8m/s at t = 0, find velocity of rain with respect to man at t = 3 sec​

Answer 1

Answer:

10m/s

Explanation:

t=3s

a=v-u/t

2=v/t

2=v/3

v=6m/s

velocity of rainwith respect to man

v(r)=8m/s

v(m)=6m/s

√(8^2+6^2)

√100

=10m/s