A man strolls from his home to the railroad station. On the off chance that he strolls at 5km/hr he misses a train by 7 minutes. However on the off chance that hee strolls at 6km/hr he achieves at the station 5 min before the flight of the train. Discover the separation secured by him to achieve the station
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Step-by-step explanation:
the answer is 6kms
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Hence, the separation secured by him to achieve the station is 6km.
Given:
- A man strolls at 5km/hr he misses a train by 7 minutes
- He strolls at 6km/hr he achieves at the station 5 min before the flight of the train
To find:
The separation secured by him to achieve the station.
Solution:
We can simply solve this question by using the following process.
Now,
We can assume that the separation secured by him to achieve the station is D.
So, the difference in time
= 7 - (-5)
= 7 + 5
= 12 minutes or 12/60 hrs
As we know, Distance = Speed × Time
So, we can say,
(D/5 - D/6) = 12/60
⇒ D(1/5 - 1/6) = 1/5
⇒ D(6 - 5/30) = 1/5
⇒ D × 1/30 = 1/5
⇒ D = 30/5
∴ D = 6 km
Hence, the separation secured by him to achieve the station is 6km.
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