a man swims across a river with speed Vm perpendicular to the flow direction of river . If water flows with with a speed Vw , with what resultant velocity does the man cross river?
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The directions of v→mandv→w are shown in the figure. Using the traingle method. The resultant velocity is given by third side of △AOC , , taken in opposite order.
AC¯¯¯¯¯=AO¯¯¯¯¯+OC¯¯¯¯¯
∣∣AC¯¯¯¯¯∣∣=AO2+OC2−−−−−−−−−−√ [ using pythogoras therem)
v2m+v2w−−−−−−−√
the direction θ the resultant makes with the v¯m is tanθ=|v¯w||v¯m|
⇒θ=tan−1(|v¯w|)|v¯m|
Explanation:
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