Question

a man swims in pool of width 300m. he covers 600m in 10 minutes by swimming from one end to other, and back along the same path. find average speed and average velocity of the man for the entire journey.
plz answer fast....​

Answer 1

Answer

• Average velocity of the man = 0 m/s
• Average speed of the man = 1 m/s

Explanation

Given:-

• Width of the pool = 300 m
• Distance covered by the man in swimming from one end to other and back along the same path = 600 m
• Time taken to cover 600 m = 10 min

To find:-

• Average speed and velocity of the man for the entire journey =?

Formula required:-

• Formula for average velocity

Average velocity = total displacement / total time taken

• Formula for average speed

Average speed = total distance covered / total time taken

Solution:-

On swimming from one end of the pool to the other, and returning back along the same path

• total displacement = zero
• total distance covered = 600 m  (given)
• total time taken by the swimmer = 10 min = 10 × 60 sec = 600 sec

So, Using formulae

→ The average velocity of man = total displacement / total time taken = 0 / 600 = 0 m/s

and

→ The average speed of man = total distance covered / total time taken = 600 / 600 = 1 m/s

       

Therefore,

• Average velocity of the man = 0 m/s
• Average speed of the man = 1 m/s.

Answer 2

$\Large\bf{\color{indigo}GiVeN,}$

• Width of a swimming pool is 300 m.

• A man covers 600 m in 10 minutes by swimming from one end to other & back along the same path.

$\bf\blue{We\:know\:that,}$

$\red\bigstar\:\:\bf{\color{peru}Average\:Speed\:=\:\dfrac{Total\:distance}{Total\:time}\:}$

☆ Here total distance covered by man is 600 m. Because he swims from one end to other & returns to the starting point, means he covered 2 times the width of swimming pool in 10 minutes.

• Total distance = 600 m

• Total time = 10 min. = 10 × 60 = 600 s

$:\implies\:\:\bf{Average\:Speed\:=\:\dfrac{600}{600}\:}$

$:\implies\:\:\bf\purple{Average\:Speed\:=\:1\:m/s\:}$

$\Large\bold\therefore$ Average speed of the man is 1 m/s.

$\bf\pink{Again\:we\:know\:that,}$

$\green\bigstar\:\:\bf{\color{olive}Average\:Velocity\:=\:\dfrac{Total\:displacement}{Total\:time}\:}$

☆ Here total displacement of the man is 0 m. Because the point from where he started his swim, at the same point his journey end, Means first he swims 300 m and returns back on the same path in 10 minutes.

• Total displacement = 0 m

• Total time = 10 min. = 600 s

$:\implies\:\:\bf{Average\:Velocity\:=\:\dfrac{0}{600}\:}$

$:\implies\:\:\bf\orange{Average\:Velocity\:=\:0\:m/s\:}$

$\Large\bold\therefore$ Average velocity of the man is 0 m/s.