Question

a man takes 10 hours to go to a place and come back by walking both the ways. he could have gained 2 hours by riding both the ways. the distance covered in the whole journey is 18 miles. find the average speed for the journey if he goes by walking and comes back by riding

Answer 1

Answer:

1.65 miles/hour

Step-by-step explanation:

The man takes 10 hours to go to a place by walking and coming back by same means.

When he rides, he takes 2 more hours.

Well this is a little (a lot) bit down to Earth types question. The questioner must be high. But we can solve this.

By riding he takes 12 hours to go and come back 18 miles.

So, We take the relation Speed=Distance/Time

So for riding, the speed will be 18/12 = 1.5 miles/hour

For walking, the speed would be 18/10 = 1.8 miles/hour

That is slow indeed. But this is just another one of those questions.

Well we need to calculate average speed.

By taking average of both the speeds we got in the first two cases, we can get the average speed.

We have, Average Speed = (Riding speed + Walking speed)/2

That is, average speed = (1.5 + 1.8)/2

So your final answer is 1.65 miles/hour

Answer 2

Given :

Time taken while walking both the way = t = 10 hours

The time taken by riding both the way = T = 10 - 2 = 8 hours

Total distance to cover = 18 miles

To Find :

The average speed for the whole journey if he goes by  walking and comes back by riding

Solution :

Let the average speed of walking = w miles/h

The average speed of riding = r miles/h

∵  For riding

Speed = $\dfrac{18 miles}{8 hours}$

          = 2.25 miles/h

For walking

Speed =   $\dfrac{18 miles}{10 hours}$

            = 1.8 miles/h

Now,

Average speed = $\dfrac{Total speed}{2}$

                          = $\dfrac{2.25 miles/h+1.8 miles/h}{2}$

                          = $\dfrac{4.05}{2}$

                          = 2.025 miles/h

Hence,  the average speed for the whole journey if he goes by walking and comes back by riding is 2.025 miles/h  Answer