Question

A man takes a loan of Rs.20,000 at a compound interest rate of 10% per
annum, then amount after one year and compound interest for two years
are​

Answer 1

✬ Amount = Rs 22000 ✬

✬ C.I = Rs 22200 ✬

Step-by-step explanation:

Given:

• Principal is Rs 20,000.
• Rate is 10% per annum.
• Time is 1 year.

To Find:

• What will be amount after 1 year and C.I for two years ?

Solution: Here we have

• P = 20000
• R = 10%
• T¹ = 1 years
• T² = 2 years

As we know that

★ Amount = P (1 + R/100)ⁿ ★

★ Amount = P + C.I ★

[ Finding amount for 1 years ]

$\implies{\rm }$ 20000(1 + 10/100)¹

$\implies{\rm }$ 20000(110/100)

$\implies{\rm }$ 200(110)

$\implies{\rm }$ 22000

So, amount after 1 year will be Rs 22000.

[ Now finding C.I for two years ]

$\implies{\rm }$ 20000(1 + 10/100)²

$\implies{\rm }$ 20000(110/100)²

$\implies{\rm }$ 20000(11/10)²

$\implies{\rm }$ 20000(121/100)

$\implies{\rm }$ 200(121)

$\implies{\rm }$ 24200

∴ A = P + C.I

=> 24200 = 2000 + C.I

=> 24200 – 2000 = C.I

=> 22200

So, C.I after 2 years will be Rs 22200.

Answer 2

✬ Amount = Rs 22000 ✬

✬ C.I = Rs 22200 ✬

Step-by-step explanation:

Given:

Principal is Rs 20,000.

Rate is 10% per annum.

Time is 1 year.

To Find:

What will be amount after 1 year and C.I for two years ?

Solution: Here we have

P = 20000

R = 10%

T¹ = 1 years

T² = 2 years

As we know that

★ Amount = P (1 + R/100)ⁿ ★

★ Amount = P + C.I ★

[ Finding amount for 1 years ]

⟹ 20000(1 + 10/100)¹

⟹ 20000(110/100)

⟹ 200(110)

⟹ 22000

So, amount after 1 year will be Rs 22000.

[ Now finding C.I for two years ]

⟹ 20000(1 + 10/100)²

⟹ 20000(110/100)²

⟹ 20000(11/10)²

⟹ 20000(121/100)

⟹ 200(121)

⟹ 24200

∴ A = P + C.I

=> 24200 = 2000 + C.I

=> 24200 – 2000 = C.I

=> 22200

So, C.I after 2 years will be Rs 22200.