Question

A man threw a stone vertically upwards from a point and it strikes the ground with a velocity of 8m/s. Find the highest point reached above the ground (m). Take g=9.8m/s²​

Answer 1

Given V=16m/s, time t=4s. Let height h, and Horizontal range R

Velocity in upward direction V

y

​

=Vsin(30

o

)=8m/s,

Velocity in horizontal V

x

​

=Vcos(30

o

)=8

3

​

In upward direction, Using s=ut+

2

1

​

at

2

⇒h=8×4−

2

1

​

×9.8×4

2

   ⇒h=−46.4 , Hence, Height=46.4m,

In horizontal direction, Range=V

x

​

×t

⇒R=8

3

​

×4=32

3

​

m, Hence Range is 32

3

​

m