Physics, asked by praneeth3090, 5 months ago

A man throws a ball of mass 0.4 kg vertically upwards with velocity of 10 m/s. What

will be its initial momentum? What would be its momentum at the highest point of its

reach?​

Answers

Answered by sahil5974
2

Explanation:

Initial Momentum = mu = 0.4 x 10 = 4 kg. m/s. At highest point of reach its final velocity will be zero. So final momentum = mv = 0.4 x 0 = 0 kg.

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Answered by Anonymous
65

Explanation :

Given,

  • Initial velocity (u) = 10 m/s
  • Mass (m) = 0.4 kg

To Find,

  1. Initial momentum of a ball.
  2. What would be its momentum at the highest point of its reach?

Solution,

Case (I), Initial momentum of a ball.

Applying momentum formula,

Pi = mu

Here,

  • Pi = Initial momentum
  • u = Initial velocity
  • m = Mass

[ Put the values in above formula ]

⇒ Pi = 0.4 × 10

Pi = 4 kg.m/s

Case (II), What would be its momentum at the highest point of its reach?

We know that,

At the highest point, the final velocity of ball is 0.

⇒ Final velocity (v) = 0 m/s

Applying momentum formula,

P = mv

  • P = Momentum
  • m = Mass
  • v = Final velocity

[ Put the values ]

⇒ P = 0.4 × 0

P = 0 kg.m/s

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