A man throws a ball of mass 0.4 kg vertically upwards with velocity of 10 m/s. What
will be its initial momentum? What would be its momentum at the highest point of its
reach?
Answers
Answered by
2
Explanation:
Initial Momentum = mu = 0.4 x 10 = 4 kg. m/s. At highest point of reach its final velocity will be zero. So final momentum = mv = 0.4 x 0 = 0 kg.
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Answered by
65
Explanation :
Given,
- Initial velocity (u) = 10 m/s
- Mass (m) = 0.4 kg
To Find,
- Initial momentum of a ball.
- What would be its momentum at the highest point of its reach?
Solution,
Case (I), Initial momentum of a ball.
Applying momentum formula,
Pi = mu
Here,
- Pi = Initial momentum
- u = Initial velocity
- m = Mass
[ Put the values in above formula ]
⇒ Pi = 0.4 × 10
⇒ Pi = 4 kg.m/s
Case (II), What would be its momentum at the highest point of its reach?
We know that,
At the highest point, the final velocity of ball is 0.
⇒ Final velocity (v) = 0 m/s
Applying momentum formula,
P = mv
- P = Momentum
- m = Mass
- v = Final velocity
[ Put the values ]
⇒ P = 0.4 × 0
⇒ P = 0 kg.m/s
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