Question

A man throws a ball of mass 0.5 kg vertically upwards with a speed of 10 ms– 1. What will be its initial momentum ? What would be its momentum after a time of 0.5 sec and at the highest point ?

Answer 1

Explanation:

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the initial velocity of the ball is 10m/s.

as it goes up the gravity will pull its velocity down with deceleration of g m/s^2.

the velocity after a time t=0.5 sec.

v = initial vel (u) - g. t = 10 m/s - gm/s^2 . 0.5 s

v = 10 - 9.8 . 0.5 = 5.1 m/s

the momentum after 0.5 s will be = mass . velocity = 0.5kg . 5.1 m/s

= 2.55 kg m/s

as the body reaches the maximum height its velocity v = zero

therefore the momentum at maximum height = m.v = 0