a man throws A ball of mass 0.5 kg vertically upwards with a velocity of 20 m/s what will be its initial Momentum ? what would be the momentum at the highest point of its reach ?
Answers
■Since mass remains constant .
■Initial velocity = 20
; initial momentum = (0.5)×(20)
==》 10 N/m^2
■ final velocity = at maximum height velocity
becomes zero.
; final momentum = (0.5)×0
==》0. N/m^2 .
Answer:
here is the answer
Step-by-step explanation:
To Find
◈ Its initial momentum?
Solution
Concept
»» So we know that here when the ball is thrown up the velocity will be 10 m/s and so we shall simply substitute the values we in the formula we May get our initial momentum
»» For the final momentum, the final velocity will be zero(0) This is because when the body reaches the highest point then its velocity will be zero and if it had anything more then it should have reached much higher.
━━━━━━━
So we know that momentum of a body is given by,
›› Momentum = Mass × Velocity
Then the initial momentum will be,
Mass = 0.4 kg
Initial velocity = 10 m/s
➝ Momentum = Mass × Initial Velocity
➝ Momentum = 0.4 × 10
➝ Initial Momentum = 4 kgm/s
Then the final momentum of the body will be,
➳ Momentum = Mass × Final Velocity
Mass = 0.4 kg
Final Velocity = 0 m/s
➳ Momentum = 0.4 × 0
➳ Final Momentum = 0 kgm/s
Therefore The Fm will be zero and the initial momentum will be 4 kgm/s
━━━━━━━━━━━━━━━━