Question

a man throws A ball of mass 0.5 kilogram vertically upward with a velocity of 25 metre per second find the initial momentum of the ball​

Answer 1

Answer:

6.25√2 kgm/s

Explanation:

Mass of the ball = 0.5kg (Given)

Upward velocity = u =25m/s (Given)

According to the equation -

p = u × m

= 0.5 × 25

= 12.5kg m/s

Maximum height = u²/2g

= (25)²/2×10

= 625/20

= 31.25 m

Thus, half of the maximum height = 31.25/2 = 15.625 m

v² = u² -2gh

v² = (25)² - 2 × 10 × (15.625)

V² = 625 - 312.5 = 312.5

V = 12.5√2 m/s

Momentum at the half of maximum height = mass × velocity at half of maximum height

= 0.5 × 12.5 √2

= 6.25√2 kgm/s