Question

A man throws a ball of mass 0.5kg vertically upwards with a velocity of 10m/s. what would be its initial velocity. what would be its momentum at highest point of reach.

please give the answer with proper steps. only for science students.

Answer 1

a) initial momentum of the ball :
mass=0.5kg
u=25m/s
p₁=uxm
=0.5 x 25
=12.5kg m/s
b) By V² - u² = 2as
s= V² - u²/2a
u= 25m/s
g=-10m/s²
V=0 m/s (final velocity)
(0-25)²/2x -10
=31.25m (  Max. height attained)
so velocity at mid point:
s/2=31.25/2=15.625m will be
v²= u² +2a(s/2)
=25²+2x(-10)x(15.625)
v²=31.25
v=17.67m/s
momentum at half way =P(half)= mv
                                                 =0.5x17.67
                                                 = 8.835 Kg -m/s